Corral Antisymmetric Multiplicative. Follow regular Corral clues (draw a loop following grid lines so all numbers are inside the loop). For each clue, let be the number of cells that belong in the loop, all in the same row, all connected, and contains this clue’s square. Define similarly for cells in the same column. For each pair of symmetric clues (with respect to center), exactly one of them gives ; the other gives .
…so I can’t think up a story. I shouldn’t be typing this while Russia vs Macau is going in osu! World Cup 3… Easy-medium puzzle.
UPDATE (9-Dec-2012, 20:06): Fixed ambiguity in bottom middle.
Enjoy. No particular comment.