corral antisymmetric multiplicative

Corral Antisymmetric Multiplicative. Follow regular Corral clues (draw a loop following grid lines so all numbers are inside the loop). For each clue, let $h$ be the number of cells that belong in the loop, all in the same row, all connected, and contains this clue’s square. Define $v$ similarly for cells in the same column. For each pair of symmetric clues (with respect to center), exactly one of them gives $h+v-1$ ; the other gives $hv$ .